Tim had some kiwis and persimmons. The number of kiwis and persimmons left were the same after Tim sold
15 of the kiwis and
57 of the persimmons. If he had 55 kiwis at first,
- How many kiwis were left?
- How many persimmons did Tim have at first?
| |
Kiwis |
Persimmons |
Before |
5x1 =
5 u |
7 u |
Change |
- 1x1 =
- 4 u |
- 5 u |
After |
4x1 =
4 u |
2 u |
(a)
Fraction of the kiwis left
= 1 -
15 =
45 Fraction of the persimmons left
= 1 -
57 =
27The number of kiwis and persimmons left were the same. Make the number of kiwis and persimmons left the same. LCM of 4 and 2 is 4.
Number of kiwis at first = 5 u
Number of persimmons at first = 7 u
5 u = 55
1 u = 55 ÷ 5 = 11
Number of kiwis left
= 2 u
= 2 x 11
= 22
(b)
Number of persimmons at first
= 7 u
= 7 x 11
= 77
Answer(s): (a) 22; (b) 77
