David had some persimmons and chikoos. The number of persimmons and chikoos left were the same after David sold
15 of the persimmons and
57 of the chikoos. If he had 90 persimmons at first,
- How many persimmons were left?
- How many chikoos did David have at first?
| |
Persimmons |
Chikoos |
Before |
5x1 =
5 u |
7 u |
Change |
- 1x1 =
- 4 u |
- 5 u |
After |
4x1 =
4 u |
2 u |
(a)
Fraction of the persimmons left
= 1 -
15 =
45 Fraction of the chikoos left
= 1 -
57 =
27The number of persimmons and chikoos left were the same. Make the number of persimmons and chikoos left the same. LCM of 4 and 2 is 4.
Number of persimmons at first = 5 u
Number of chikoos at first = 7 u
5 u = 90
1 u = 90 ÷ 5 = 18
Number of persimmons left
= 2 u
= 2 x 18
= 36
(b)
Number of chikoos at first
= 7 u
= 7 x 18
= 126
Answer(s): (a) 36; (b) 126
