Wesley had some oranges and peaches. The number of oranges and peaches left were the same after Wesley sold
15 of the oranges and
47 of the peaches. If he had 105 oranges at first,
- How many oranges were left?
- How many peaches did Wesley have at first?
| |
Oranges |
Peaches |
Before |
5x3 =
15 u |
7 u |
Change |
- 1x3 =
- 12 u |
- 4 u |
After |
4x3 =
12 u |
3 u |
(a)
Fraction of the oranges left
= 1 -
15 =
45 Fraction of the peaches left
= 1 -
47 =
37The number of oranges and peaches left were the same. Make the number of oranges and peaches left the same. LCM of 4 and 3 is 12.
Number of oranges at first = 15 u
Number of peaches at first = 7 u
15 u = 105
1 u = 105 ÷ 15 = 7
Number of oranges left
= 3 u
= 3 x 7
= 21
(b)
Number of peaches at first
= 7 u
= 7 x 7
= 49
Answer(s): (a) 21; (b) 49
