Billy had some apples and chikoos. The number of apples and chikoos left were the same after Billy sold
12 of the apples and
35 of the chikoos. If he had 92 apples at first,
- How many apples were left?
- How many chikoos did Billy have at first?
| |
Apples |
Chikoos |
Before |
2x2 =
4 u |
5 u |
Change |
- 1x2 =
- 2 u |
- 3 u |
After |
1x2 =
2 u |
2 u |
(a)
Fraction of the apples left
= 1 -
12 =
12 Fraction of the chikoos left
= 1 -
35 =
25The number of apples and chikoos left were the same. Make the number of apples and chikoos left the same. LCM of 1 and 2 is 2.
Number of apples at first = 4 u
Number of chikoos at first = 5 u
4 u = 92
1 u = 92 ÷ 4 = 23
Number of apples left
= 2 u
= 2 x 23
= 46
(b)
Number of chikoos at first
= 5 u
= 5 x 23
= 115
Answer(s): (a) 46; (b) 115
