Paul had some pomegranates and dragonfruits. The number of pomegranates and dragonfruits left were the same after Paul sold
12 of the pomegranates and
47 of the dragonfruits. If he had 78 pomegranates at first,
- How many pomegranates were left?
- How many dragonfruits did Paul have at first?
|
Pomegranates |
Dragonfruits |
Before |
2x3 = 6 u |
7 u |
Change |
- 1x3 = - 3 u |
- 4 u |
After |
1x3 = 3 u |
3 u |
(a)
Fraction of the pomegranates left
= 1 -
12 =
12 Fraction of the dragonfruits left
= 1 -
47 =
37The number of pomegranates and dragonfruits left were the same. Make the number of pomegranates and dragonfruits left the same. LCM of 1 and 3 is 3.
Number of pomegranates at first = 6 u
Number of dragonfruits at first = 7 u
6 u = 78
1 u = 78 ÷ 6 = 13
Number of pomegranates left
= 3 u
= 3 x 13
= 39
(b)
Number of dragonfruits at first
= 7 u
= 7 x 13
= 91
Answer(s): (a) 39; (b) 91