Jeremy had some persimmons and chikoos. The number of persimmons and chikoos left were the same after Jeremy sold
12 of the persimmons and
37 of the chikoos. If he had 112 persimmons at first,
- How many persimmons were left?
- How many chikoos did Jeremy have at first?
| |
Persimmons |
Chikoos |
Before |
2x4 =
8 u |
7 u |
Change |
- 1x4 =
- 4 u |
- 3 u |
After |
1x4 =
4 u |
4 u |
(a)
Fraction of the persimmons left
= 1 -
12 =
12 Fraction of the chikoos left
= 1 -
37 =
47The number of persimmons and chikoos left were the same. Make the number of persimmons and chikoos left the same. LCM of 1 and 4 is 4.
Number of persimmons at first = 8 u
Number of chikoos at first = 7 u
8 u = 112
1 u = 112 ÷ 8 = 14
Number of persimmons left
= 4 u
= 4 x 14
= 56
(b)
Number of chikoos at first
= 7 u
= 7 x 14
= 98
Answer(s): (a) 56; (b) 98
