Pierre had some oranges and pears. The number of oranges and pears left were the same after Pierre sold
35 of the oranges and
37 of the pears. If he had 50 oranges at first,
- How many oranges were left?
- How many pears did Pierre have at first?
| |
Oranges |
Pears |
Before |
5x2 =
10 u |
7 u |
Change |
- 3x2 =
- 4 u |
- 3 u |
After |
2x2 =
4 u |
4 u |
(a)
Fraction of the oranges left
= 1 -
35 =
25 Fraction of the pears left
= 1 -
37 =
47The number of oranges and pears left were the same. Make the number of oranges and pears left the same. LCM of 2 and 4 is 4.
Number of oranges at first = 10 u
Number of pears at first = 7 u
10 u = 50
1 u = 50 ÷ 10 = 5
Number of oranges left
= 4 u
= 4 x 5
= 20
(b)
Number of pears at first
= 7 u
= 7 x 5
= 35
Answer(s): (a) 20; (b) 35
