Jack had some persimmons and grapefruits. The number of persimmons and grapefruits left were the same after Jack sold
12 of the persimmons and
57 of the grapefruits. If he had 88 persimmons at first,
- How many persimmons were left?
- How many grapefruits did Jack have at first?
| |
Persimmons |
Grapefruits |
Before |
2x2 =
4 u |
7 u |
Change |
- 1x2 =
- 2 u |
- 5 u |
After |
1x2 =
2 u |
2 u |
(a)
Fraction of the persimmons left
= 1 -
12 =
12 Fraction of the grapefruits left
= 1 -
57 =
27The number of persimmons and grapefruits left were the same. Make the number of persimmons and grapefruits left the same. LCM of 1 and 2 is 2.
Number of persimmons at first = 4 u
Number of grapefruits at first = 7 u
4 u = 88
1 u = 88 ÷ 4 = 22
Number of persimmons left
= 2 u
= 2 x 22
= 44
(b)
Number of grapefruits at first
= 7 u
= 7 x 22
= 154
Answer(s): (a) 44; (b) 154
