Vincent had some pears and guavas. The number of pears and guavas left were the same after Vincent sold
23 of the pears and
35 of the guavas. If he had 60 pears at first,
- How many pears were left?
- How many guavas did Vincent have at first?
| |
Pears |
Guavas |
Before |
3x2 =
6 u |
5 u |
Change |
- 2x2 =
- 2 u |
- 3 u |
After |
1x2 =
2 u |
2 u |
(a)
Fraction of the pears left
= 1 -
23 =
13 Fraction of the guavas left
= 1 -
35 =
25The number of pears and guavas left were the same. Make the number of pears and guavas left the same. LCM of 1 and 2 is 2.
Number of pears at first = 6 u
Number of guavas at first = 5 u
6 u = 60
1 u = 60 ÷ 6 = 10
Number of pears left
= 2 u
= 2 x 10
= 20
(b)
Number of guavas at first
= 5 u
= 5 x 10
= 50
Answer(s): (a) 20; (b) 50
