Perry had some oranges and peaches. The number of oranges and peaches left were the same after Perry sold
12 of the oranges and
37 of the peaches. If he had 72 oranges at first,
- How many oranges were left?
- How many peaches did Perry have at first?
| |
Oranges |
Peaches |
Before |
2x4 =
8 u |
7 u |
Change |
- 1x4 =
- 4 u |
- 3 u |
After |
1x4 =
4 u |
4 u |
(a)
Fraction of the oranges left
= 1 -
12 =
12 Fraction of the peaches left
= 1 -
37 =
47The number of oranges and peaches left were the same. Make the number of oranges and peaches left the same. LCM of 1 and 4 is 4.
Number of oranges at first = 8 u
Number of peaches at first = 7 u
8 u = 72
1 u = 72 ÷ 8 = 9
Number of oranges left
= 4 u
= 4 x 9
= 36
(b)
Number of peaches at first
= 7 u
= 7 x 9
= 63
Answer(s): (a) 36; (b) 63
