Min had $29 more than Xuan at first. Xuan spent
49 of her money and Min spent
12 of her money. Given that they had equal amount of money left, how many much did Xuan have at first?
| |
Min |
Xuan |
More |
Before |
9x1 =
9 u |
2x5 =
10 u |
1 u |
Change |
- 4x1 =
- 4 u |
- 1x5 =
- 5 u |
|
After |
5x1 =
5 u |
1x5 =
5 u |
|
Fraction of money that Xuan had left
= 1 -
49 =
59 Fraction of money that Min had left
= 1 -
12 =
12 The amount that Min and Xuan had left is the same. Make the amount that Min and Xuan had left is the same. LCM of 5 and 1 is 5.
Amount that Xuan had at first = 9 u
Amount that Min had at first = 10 u
Amount that Min had more than Xuan at first
= 10 u - 9 u
= 1 u
= $29
Amount that Xuan had at first
= 9 u
= 9 x 29
= $261
Answer(s): $261
