Sabrina had $19 more than Xylia at first. Xylia spent
25 of her money and Sabrina spent
12 of her money. Given that they had equal amount of money left, how many much did Xylia have at first?
| |
Sabrina |
Xylia |
More |
Before |
5x1 =
5 u |
2x3 =
6 u |
1 u |
Change |
- 2x1 =
- 2 u |
- 1x3 =
- 3 u |
|
After |
3x1 =
3 u |
1x3 =
3 u |
|
Fraction of money that Xylia had left
= 1 -
25 =
35 Fraction of money that Sabrina had left
= 1 -
12 =
12 The amount that Sabrina and Xylia had left is the same. Make the amount that Sabrina and Xylia had left is the same. LCM of 3 and 1 is 3.
Amount that Xylia had at first = 5 u
Amount that Sabrina had at first = 6 u
Amount that Sabrina had more than Xylia at first
= 6 u - 5 u
= 1 u
= $19
Amount that Xylia had at first
= 5 u
= 5 x 19
= $95
Answer(s): $95
