Irene had $29 more than Hilda at first. Hilda spent
79 of her money and Irene spent
45 of her money. Given that they had equal amount of money left, how many much did Hilda have at first?
| |
Irene |
Hilda |
More |
Before |
9x1 =
9 u |
5x2 =
10 u |
1 u |
Change |
- 7x1 =
- 7 u |
- 4x2 =
- 8 u |
|
After |
2x1 =
2 u |
1x2 =
2 u |
|
Fraction of money that Hilda had left
= 1 -
79 =
29 Fraction of money that Irene had left
= 1 -
45 =
15 The amount that Irene and Hilda had left is the same. Make the amount that Irene and Hilda had left is the same. LCM of 2 and 1 is 2.
Amount that Hilda had at first = 9 u
Amount that Irene had at first = 10 u
Amount that Irene had more than Hilda at first
= 10 u - 9 u
= 1 u
= $29
Amount that Hilda had at first
= 9 u
= 9 x 29
= $261
Answer(s): $261
