Jean had $19 more than Roshel at first. Roshel spent
49 of her money and Jean spent
12 of her money. Given that they had equal amount of money left, how many much did Roshel have at first?
| |
Jean |
Roshel |
More |
Before |
9x1 =
9 u |
2x5 =
10 u |
1 u |
Change |
- 4x1 =
- 4 u |
- 1x5 =
- 5 u |
|
After |
5x1 =
5 u |
1x5 =
5 u |
|
Fraction of money that Roshel had left
= 1 -
49 =
59 Fraction of money that Jean had left
= 1 -
12 =
12 The amount that Jean and Roshel had left is the same. Make the amount that Jean and Roshel had left is the same. LCM of 5 and 1 is 5.
Amount that Roshel had at first = 9 u
Amount that Jean had at first = 10 u
Amount that Jean had more than Roshel at first
= 10 u - 9 u
= 1 u
= $19
Amount that Roshel had at first
= 9 u
= 9 x 19
= $171
Answer(s): $171
