Yoko had $170 more than Albert. Yoko spent
56 of her money and Albert spent
58 of his money. In the end, Albert and Yoko had the same amount of money left. Find the amount of money Albert had at first.
| |
Yoko |
Albert |
More |
Before |
6x3 =
18 u |
8 u |
10 u |
Change |
- 5x3 =
- 15 u |
- 5 u |
|
After |
1x3 =
3 u |
3 u |
|
Fraction of money that Yoko left
= 1 -
56 =
16 Fraction of money that Albert left
= 1 -
58 =
38 The amount of money that Albert and Yoko had in the end is the same. Make the amount of money that Albert and Yoko had in the end the same. LCM of 1 and 3 is 3.
Amount that Yoko had more than Albert at first
= 18 u - 8 u
= 10 u
10 u = 170
1 u = 170 ÷ 10 = 17
Amount that Albert had at first
= 8 u
= 8 x 17
= $136
Answer(s): $136
