Marion had $120 more than Billy. Marion spent
12 of her money and Billy spent
38 of his money. In the end, Billy and Marion had the same amount of money left. Find the amount of money Billy had at first.
| |
Marion |
Billy |
More |
Before |
2x5 =
10 u |
8 u |
2 u |
Change |
- 1x5 =
- 5 u |
- 3 u |
|
After |
1x5 =
5 u |
5 u |
|
Fraction of money that Marion left
= 1 -
12 =
12 Fraction of money that Billy left
= 1 -
38 =
58 The amount of money that Billy and Marion had in the end is the same. Make the amount of money that Billy and Marion had in the end the same. LCM of 1 and 5 is 5.
Amount that Marion had more than Billy at first
= 10 u - 8 u
= 2 u
2 u = 120
1 u = 120 ÷ 2 = 60
Amount that Billy had at first
= 8 u
= 8 x 60
= $480
Answer(s): $480
