Joelle had $195 more than Albert. Joelle spent
56 of her money and Albert spent
59 of his money. In the end, Albert and Joelle had the same amount of money left. Find the amount of money Albert had at first.
| |
Joelle |
Albert |
More |
Before |
6x4 =
24 u |
9 u |
15 u |
Change |
- 5x4 =
- 20 u |
- 5 u |
|
After |
1x4 =
4 u |
4 u |
|
Fraction of money that Joelle left
= 1 -
56 =
16 Fraction of money that Albert left
= 1 -
59 =
49 The amount of money that Albert and Joelle had in the end is the same. Make the amount of money that Albert and Joelle had in the end the same. LCM of 1 and 4 is 4.
Amount that Joelle had more than Albert at first
= 24 u - 9 u
= 15 u
15 u = 195
1 u = 195 ÷ 15 = 13
Amount that Albert had at first
= 9 u
= 9 x 13
= $117
Answer(s): $117
