Elyse had $153 more than Brandon. Elyse spent
35 of her money and Brandon spent
37 of his money. In the end, Brandon and Elyse had the same amount of money left. Find the amount of money Brandon had at first.
| |
Elyse |
Brandon |
More |
Before |
5x2 =
10 u |
7 u |
3 u |
Change |
- 3x2 =
- 6 u |
- 3 u |
|
After |
2x2 =
4 u |
4 u |
|
Fraction of money that Elyse left
= 1 -
35 =
25 Fraction of money that Brandon left
= 1 -
37 =
47 The amount of money that Brandon and Elyse had in the end is the same. Make the amount of money that Brandon and Elyse had in the end the same. LCM of 2 and 4 is 4.
Amount that Elyse had more than Brandon at first
= 10 u - 7 u
= 3 u
3 u = 153
1 u = 153 ÷ 3 = 51
Amount that Brandon had at first
= 7 u
= 7 x 51
= $357
Answer(s): $357
