Marion had $192 more than Ken. Marion spent
56 of her money and Ken spent
79 of his money. In the end, Ken and Marion had the same amount of money left. Find the amount of money Ken had at first.
| |
Marion |
Ken |
More |
Before |
6x2 =
12 u |
9 u |
3 u |
Change |
- 5x2 =
- 10 u |
- 7 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Marion left
= 1 -
56 =
16 Fraction of money that Ken left
= 1 -
79 =
29 The amount of money that Ken and Marion had in the end is the same. Make the amount of money that Ken and Marion had in the end the same. LCM of 1 and 2 is 2.
Amount that Marion had more than Ken at first
= 12 u - 9 u
= 3 u
3 u = 192
1 u = 192 ÷ 3 = 64
Amount that Ken had at first
= 9 u
= 9 x 64
= $576
Answer(s): $576
