Sarah had $182 more than Riordan. Sarah spent
23 of her money and Riordan spent
47 of his money. In the end, Riordan and Sarah had the same amount of money left. Find the amount of money Riordan had at first.
| |
Sarah |
Riordan |
More |
Before |
3x3 =
9 u |
7 u |
2 u |
Change |
- 2x3 =
- 6 u |
- 4 u |
|
After |
1x3 =
3 u |
3 u |
|
Fraction of money that Sarah left
= 1 -
23 =
13 Fraction of money that Riordan left
= 1 -
47 =
37 The amount of money that Riordan and Sarah had in the end is the same. Make the amount of money that Riordan and Sarah had in the end the same. LCM of 1 and 3 is 3.
Amount that Sarah had more than Riordan at first
= 9 u - 7 u
= 2 u
2 u = 182
1 u = 182 ÷ 2 = 91
Amount that Riordan had at first
= 7 u
= 7 x 91
= $637
Answer(s): $637
