Sabrina had $135 more than Luis. Sabrina spent
23 of her money and Luis spent
13 of his money. In the end, Luis and Sabrina had the same amount of money left. Find the amount of money Luis had at first.
| |
Sabrina |
Luis |
More |
Before |
3x2 =
6 u |
3 u |
3 u |
Change |
- 2x2 =
- 4 u |
- 1 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Sabrina left
= 1 -
23 =
13 Fraction of money that Luis left
= 1 -
13 =
23 The amount of money that Luis and Sabrina had in the end is the same. Make the amount of money that Luis and Sabrina had in the end the same. LCM of 1 and 2 is 2.
Amount that Sabrina had more than Luis at first
= 6 u - 3 u
= 3 u
3 u = 135
1 u = 135 ÷ 3 = 45
Amount that Luis had at first
= 3 u
= 3 x 45
= $135
Answer(s): $135
