Abi had $110 more than Ken. Abi spent
23 of her money and Ken spent
47 of his money. In the end, Ken and Abi had the same amount of money left. Find the amount of money Ken had at first.
| |
Abi |
Ken |
More |
Before |
3x3 =
9 u |
7 u |
2 u |
Change |
- 2x3 =
- 6 u |
- 4 u |
|
After |
1x3 =
3 u |
3 u |
|
Fraction of money that Abi left
= 1 -
23 =
13 Fraction of money that Ken left
= 1 -
47 =
37 The amount of money that Ken and Abi had in the end is the same. Make the amount of money that Ken and Abi had in the end the same. LCM of 1 and 3 is 3.
Amount that Abi had more than Ken at first
= 9 u - 7 u
= 2 u
2 u = 110
1 u = 110 ÷ 2 = 55
Amount that Ken had at first
= 7 u
= 7 x 55
= $385
Answer(s): $385
