Xuan had $168 more than Xavier. Xuan spent
23 of her money and Xavier spent
49 of his money. In the end, Xavier and Xuan had the same amount of money left. Find the amount of money Xavier had at first.
| |
Xuan |
Xavier |
More |
Before |
3x5 =
15 u |
9 u |
6 u |
Change |
- 2x5 =
- 10 u |
- 4 u |
|
After |
1x5 =
5 u |
5 u |
|
Fraction of money that Xuan left
= 1 -
23 =
13 Fraction of money that Xavier left
= 1 -
49 =
59 The amount of money that Xavier and Xuan had in the end is the same. Make the amount of money that Xavier and Xuan had in the end the same. LCM of 1 and 5 is 5.
Amount that Xuan had more than Xavier at first
= 15 u - 9 u
= 6 u
6 u = 168
1 u = 168 ÷ 6 = 28
Amount that Xavier had at first
= 9 u
= 9 x 28
= $252
Answer(s): $252
