Shannon had $147 more than Cole. Shannon spent
23 of her money and Cole spent
13 of his money. In the end, Cole and Shannon had the same amount of money left. Find the amount of money Cole had at first.
| |
Shannon |
Cole |
More |
Before |
3x2 =
6 u |
3 u |
3 u |
Change |
- 2x2 =
- 4 u |
- 1 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Shannon left
= 1 -
23 =
13 Fraction of money that Cole left
= 1 -
13 =
23 The amount of money that Cole and Shannon had in the end is the same. Make the amount of money that Cole and Shannon had in the end the same. LCM of 1 and 2 is 2.
Amount that Shannon had more than Cole at first
= 6 u - 3 u
= 3 u
3 u = 147
1 u = 147 ÷ 3 = 49
Amount that Cole had at first
= 3 u
= 3 x 49
= $147
Answer(s): $147
