Kimberly had $162 more than Michael. Kimberly spent
56 of her money and Michael spent
79 of his money. In the end, Michael and Kimberly had the same amount of money left. Find the amount of money Michael had at first.
| |
Kimberly |
Michael |
More |
Before |
6x2 =
12 u |
9 u |
3 u |
Change |
- 5x2 =
- 10 u |
- 7 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Kimberly left
= 1 -
56 =
16 Fraction of money that Michael left
= 1 -
79 =
29 The amount of money that Michael and Kimberly had in the end is the same. Make the amount of money that Michael and Kimberly had in the end the same. LCM of 1 and 2 is 2.
Amount that Kimberly had more than Michael at first
= 12 u - 9 u
= 3 u
3 u = 162
1 u = 162 ÷ 3 = 54
Amount that Michael had at first
= 9 u
= 9 x 54
= $486
Answer(s): $486
