Tina had $112 more than Xavier. Tina spent
23 of her money and Xavier spent
38 of his money. In the end, Xavier and Tina had the same amount of money left. Find the amount of money Xavier had at first.
| |
Tina |
Xavier |
More |
Before |
3x5 =
15 u |
8 u |
7 u |
Change |
- 2x5 =
- 10 u |
- 3 u |
|
After |
1x5 =
5 u |
5 u |
|
Fraction of money that Tina left
= 1 -
23 =
13 Fraction of money that Xavier left
= 1 -
38 =
58 The amount of money that Xavier and Tina had in the end is the same. Make the amount of money that Xavier and Tina had in the end the same. LCM of 1 and 5 is 5.
Amount that Tina had more than Xavier at first
= 15 u - 8 u
= 7 u
7 u = 112
1 u = 112 ÷ 7 = 16
Amount that Xavier had at first
= 8 u
= 8 x 16
= $128
Answer(s): $128
