Nora had $168 more than Peter. Nora spent
23 of her money and Peter spent
13 of his money. In the end, Peter and Nora had the same amount of money left. Find the amount of money Peter had at first.
| |
Nora |
Peter |
More |
Before |
3x2 =
6 u |
3 u |
3 u |
Change |
- 2x2 =
- 4 u |
- 1 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Nora left
= 1 -
23 =
13 Fraction of money that Peter left
= 1 -
13 =
23 The amount of money that Peter and Nora had in the end is the same. Make the amount of money that Peter and Nora had in the end the same. LCM of 1 and 2 is 2.
Amount that Nora had more than Peter at first
= 6 u - 3 u
= 3 u
3 u = 168
1 u = 168 ÷ 3 = 56
Amount that Peter had at first
= 3 u
= 3 x 56
= $168
Answer(s): $168
