Jean had $160 more than Cole. Jean spent
12 of her money and Cole spent
38 of his money. In the end, Cole and Jean had the same amount of money left. Find the amount of money Cole had at first.
| |
Jean |
Cole |
More |
Before |
2x5 =
10 u |
8 u |
2 u |
Change |
- 1x5 =
- 5 u |
- 3 u |
|
After |
1x5 =
5 u |
5 u |
|
Fraction of money that Jean left
= 1 -
12 =
12 Fraction of money that Cole left
= 1 -
38 =
58 The amount of money that Cole and Jean had in the end is the same. Make the amount of money that Cole and Jean had in the end the same. LCM of 1 and 5 is 5.
Amount that Jean had more than Cole at first
= 10 u - 8 u
= 2 u
2 u = 160
1 u = 160 ÷ 2 = 80
Amount that Cole had at first
= 8 u
= 8 x 80
= $640
Answer(s): $640
