Xylia had $138 more than Will. Xylia spent
23 of her money and Will spent
59 of his money. In the end, Will and Xylia had the same amount of money left. Find the amount of money Will had at first.
| |
Xylia |
Will |
More |
Before |
3x4 =
12 u |
9 u |
3 u |
Change |
- 2x4 =
- 8 u |
- 5 u |
|
After |
1x4 =
4 u |
4 u |
|
Fraction of money that Xylia left
= 1 -
23 =
13 Fraction of money that Will left
= 1 -
59 =
49 The amount of money that Will and Xylia had in the end is the same. Make the amount of money that Will and Xylia had in the end the same. LCM of 1 and 4 is 4.
Amount that Xylia had more than Will at first
= 12 u - 9 u
= 3 u
3 u = 138
1 u = 138 ÷ 3 = 46
Amount that Will had at first
= 9 u
= 9 x 46
= $414
Answer(s): $414
