Opal had $180 more than Lee. Opal spent
23 of her money and Lee spent
13 of his money. In the end, Lee and Opal had the same amount of money left. Find the amount of money Lee had at first.
| |
Opal |
Lee |
More |
Before |
3x2 =
6 u |
3 u |
3 u |
Change |
- 2x2 =
- 4 u |
- 1 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Opal left
= 1 -
23 =
13 Fraction of money that Lee left
= 1 -
13 =
23 The amount of money that Lee and Opal had in the end is the same. Make the amount of money that Lee and Opal had in the end the same. LCM of 1 and 2 is 2.
Amount that Opal had more than Lee at first
= 6 u - 3 u
= 3 u
3 u = 180
1 u = 180 ÷ 3 = 60
Amount that Lee had at first
= 3 u
= 3 x 60
= $180
Answer(s): $180
