Xylia had $152 more than Dylan. Xylia spent
45 of her money and Dylan spent
47 of his money. In the end, Dylan and Xylia had the same amount of money left. Find the amount of money Dylan had at first.
| |
Xylia |
Dylan |
More |
Before |
5x3 =
15 u |
7 u |
8 u |
Change |
- 4x3 =
- 12 u |
- 4 u |
|
After |
1x3 =
3 u |
3 u |
|
Fraction of money that Xylia left
= 1 -
45 =
15 Fraction of money that Dylan left
= 1 -
47 =
37 The amount of money that Dylan and Xylia had in the end is the same. Make the amount of money that Dylan and Xylia had in the end the same. LCM of 1 and 3 is 3.
Amount that Xylia had more than Dylan at first
= 15 u - 7 u
= 8 u
8 u = 152
1 u = 152 ÷ 8 = 19
Amount that Dylan had at first
= 7 u
= 7 x 19
= $133
Answer(s): $133
