Marion had $110 more than Vaidev. Marion spent
56 of her money and Vaidev spent
57 of his money. In the end, Vaidev and Marion had the same amount of money left. Find the amount of money Vaidev had at first.
| |
Marion |
Vaidev |
More |
Before |
6x2 =
12 u |
7 u |
5 u |
Change |
- 5x2 =
- 10 u |
- 5 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Marion left
= 1 -
56 =
16 Fraction of money that Vaidev left
= 1 -
57 =
27 The amount of money that Vaidev and Marion had in the end is the same. Make the amount of money that Vaidev and Marion had in the end the same. LCM of 1 and 2 is 2.
Amount that Marion had more than Vaidev at first
= 12 u - 7 u
= 5 u
5 u = 110
1 u = 110 ÷ 5 = 22
Amount that Vaidev had at first
= 7 u
= 7 x 22
= $154
Answer(s): $154
