Ivory had $128 more than Pierre. Ivory spent
12 of her money and Pierre spent
38 of his money. In the end, Pierre and Ivory had the same amount of money left. Find the amount of money Pierre had at first.
| |
Ivory |
Pierre |
More |
Before |
2x5 =
10 u |
8 u |
2 u |
Change |
- 1x5 =
- 5 u |
- 3 u |
|
After |
1x5 =
5 u |
5 u |
|
Fraction of money that Ivory left
= 1 -
12 =
12 Fraction of money that Pierre left
= 1 -
38 =
58 The amount of money that Pierre and Ivory had in the end is the same. Make the amount of money that Pierre and Ivory had in the end the same. LCM of 1 and 5 is 5.
Amount that Ivory had more than Pierre at first
= 10 u - 8 u
= 2 u
2 u = 128
1 u = 128 ÷ 2 = 64
Amount that Pierre had at first
= 8 u
= 8 x 64
= $512
Answer(s): $512
