Kimberly had $186 more than Pierre. Kimberly spent
23 of her money and Pierre spent
49 of his money. In the end, Pierre and Kimberly had the same amount of money left. Find the amount of money Pierre had at first.
| |
Kimberly |
Pierre |
More |
Before |
3x5 =
15 u |
9 u |
6 u |
Change |
- 2x5 =
- 10 u |
- 4 u |
|
After |
1x5 =
5 u |
5 u |
|
Fraction of money that Kimberly left
= 1 -
23 =
13 Fraction of money that Pierre left
= 1 -
49 =
59 The amount of money that Pierre and Kimberly had in the end is the same. Make the amount of money that Pierre and Kimberly had in the end the same. LCM of 1 and 5 is 5.
Amount that Kimberly had more than Pierre at first
= 15 u - 9 u
= 6 u
6 u = 186
1 u = 186 ÷ 6 = 31
Amount that Pierre had at first
= 9 u
= 9 x 31
= $279
Answer(s): $279
