Xylia had $132 more than Gabriel. Xylia spent
23 of her money and Gabriel spent
49 of his money. In the end, Gabriel and Xylia had the same amount of money left. Find the amount of money Gabriel had at first.
| |
Xylia |
Gabriel |
More |
Before |
3x5 =
15 u |
9 u |
6 u |
Change |
- 2x5 =
- 10 u |
- 4 u |
|
After |
1x5 =
5 u |
5 u |
|
Fraction of money that Xylia left
= 1 -
23 =
13 Fraction of money that Gabriel left
= 1 -
49 =
59 The amount of money that Gabriel and Xylia had in the end is the same. Make the amount of money that Gabriel and Xylia had in the end the same. LCM of 1 and 5 is 5.
Amount that Xylia had more than Gabriel at first
= 15 u - 9 u
= 6 u
6 u = 132
1 u = 132 ÷ 6 = 22
Amount that Gabriel had at first
= 9 u
= 9 x 22
= $198
Answer(s): $198
