Opal had $150 more than Peter. Opal spent
23 of her money and Peter spent
47 of his money. In the end, Peter and Opal had the same amount of money left. Find the amount of money Peter had at first.
| |
Opal |
Peter |
More |
Before |
3x3 =
9 u |
7 u |
2 u |
Change |
- 2x3 =
- 6 u |
- 4 u |
|
After |
1x3 =
3 u |
3 u |
|
Fraction of money that Opal left
= 1 -
23 =
13 Fraction of money that Peter left
= 1 -
47 =
37 The amount of money that Peter and Opal had in the end is the same. Make the amount of money that Peter and Opal had in the end the same. LCM of 1 and 3 is 3.
Amount that Opal had more than Peter at first
= 9 u - 7 u
= 2 u
2 u = 150
1 u = 150 ÷ 2 = 75
Amount that Peter had at first
= 7 u
= 7 x 75
= $525
Answer(s): $525
