Opal had $132 more than Carl. Opal spent
23 of her money and Carl spent
59 of his money. In the end, Carl and Opal had the same amount of money left. Find the amount of money Carl had at first.
| |
Opal |
Carl |
More |
Before |
3x4 =
12 u |
9 u |
3 u |
Change |
- 2x4 =
- 8 u |
- 5 u |
|
After |
1x4 =
4 u |
4 u |
|
Fraction of money that Opal left
= 1 -
23 =
13 Fraction of money that Carl left
= 1 -
59 =
49 The amount of money that Carl and Opal had in the end is the same. Make the amount of money that Carl and Opal had in the end the same. LCM of 1 and 4 is 4.
Amount that Opal had more than Carl at first
= 12 u - 9 u
= 3 u
3 u = 132
1 u = 132 ÷ 3 = 44
Amount that Carl had at first
= 9 u
= 9 x 44
= $396
Answer(s): $396
