Irene had $195 more than Riordan. Irene spent
45 of her money and Riordan spent
57 of his money. In the end, Riordan and Irene had the same amount of money left. Find the amount of money Riordan had at first.
| |
Irene |
Riordan |
More |
Before |
5x2 =
10 u |
7 u |
3 u |
Change |
- 4x2 =
- 8 u |
- 5 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Irene left
= 1 -
45 =
15 Fraction of money that Riordan left
= 1 -
57 =
27 The amount of money that Riordan and Irene had in the end is the same. Make the amount of money that Riordan and Irene had in the end the same. LCM of 1 and 2 is 2.
Amount that Irene had more than Riordan at first
= 10 u - 7 u
= 3 u
3 u = 195
1 u = 195 ÷ 3 = 65
Amount that Riordan had at first
= 7 u
= 7 x 65
= $455
Answer(s): $455
