Abi had $120 more than Brandon. Abi spent
45 of her money and Brandon spent
35 of his money. In the end, Brandon and Abi had the same amount of money left. Find the amount of money Brandon had at first.
| |
Abi |
Brandon |
More |
Before |
5x2 =
10 u |
5 u |
5 u |
Change |
- 4x2 =
- 8 u |
- 3 u |
|
After |
1x2 =
2 u |
2 u |
|
Fraction of money that Abi left
= 1 -
45 =
15 Fraction of money that Brandon left
= 1 -
35 =
25 The amount of money that Brandon and Abi had in the end is the same. Make the amount of money that Brandon and Abi had in the end the same. LCM of 1 and 2 is 2.
Amount that Abi had more than Brandon at first
= 10 u - 5 u
= 5 u
5 u = 120
1 u = 120 ÷ 5 = 24
Amount that Brandon had at first
= 5 u
= 5 x 24
= $120
Answer(s): $120
