Betty had $172 more than Dylan. Betty spent
34 of her money and Dylan spent
58 of his money. In the end, Dylan and Betty had the same amount of money left. Find the amount of money Dylan had at first.
| |
Betty |
Dylan |
More |
Before |
4x3 =
12 u |
8 u |
4 u |
Change |
- 3x3 =
- 9 u |
- 5 u |
|
After |
1x3 =
3 u |
3 u |
|
Fraction of money that Betty left
= 1 -
34 =
14 Fraction of money that Dylan left
= 1 -
58 =
38 The amount of money that Dylan and Betty had in the end is the same. Make the amount of money that Dylan and Betty had in the end the same. LCM of 1 and 3 is 3.
Amount that Betty had more than Dylan at first
= 12 u - 8 u
= 4 u
4 u = 172
1 u = 172 ÷ 4 = 43
Amount that Dylan had at first
= 8 u
= 8 x 43
= $344
Answer(s): $344
