At the sports meet, there were 52 less girls than boys. After
25 of the girls and
49 of the boys had left the hall, there was an equal number of girls and boys that remained behind. Find the number of girls who were present at the sports meet at first.
|
Girls |
Boys |
Less |
Before |
5x5 = 25 u |
9x3 = 27 u |
2 u |
Change |
- 2x5 = - 10 u |
- 4x3 = - 12 u |
|
After |
3x5 = 15 u |
5x3 = 15 u |
|
Fraction of girls that remained
= 1 -
25 =
35 Fraction of boys that remained
= 1 -
49 =
59 The number of girls and boys in the end is the same. Make the number of girls and boys in the end the same. LCM of 3 and 5 is 15.
3x55x5 Girls =
5x39x3 Boys
1525 Girls =
1527 Boys
Total girls at first = 25 u
Total boys at first = 27 u
Number of less girls than boys at first
= 27 u - 25 u
= 2 u
2 u = 52
1 u = 52 ÷ 2 = 26
Number of girls at first
= 25 u
= 25 x 26
= 650
Answer(s): 650