At the sports meet, there were 60 less boys than girls. After
25 of the boys and
49 of the girls had left the hall, there was an equal number of boys and girls that remained behind. Find the number of boys who were present at the sports meet at first.
|
Boys |
Girls |
Less |
Before |
5x5 = 25 u |
9x3 = 27 u |
2 u |
Change |
- 2x5 = - 10 u |
- 4x3 = - 12 u |
|
After |
3x5 = 15 u |
5x3 = 15 u |
|
Fraction of boys that remained
= 1 -
25 =
35 Fraction of girls that remained
= 1 -
49 =
59 The number of boys and girls in the end is the same. Make the number of boys and girls in the end the same. LCM of 3 and 5 is 15.
3x55x5 Boys =
5x39x3 Girls
1525 Boys =
1527 Girls
Total boys at first = 25 u
Total girls at first = 27 u
Number of less boys than girls at first
= 27 u - 25 u
= 2 u
2 u = 60
1 u = 60 ÷ 2 = 30
Number of boys at first
= 25 u
= 25 x 30
= 750
Answer(s): 750