Tim and Liam shared some marbles. Tim took
57 of the marbles. After Tim lost 12 marbles, Liam had twice as many marbles as Tim. How many marbles did Liam have in the end?
| |
Tim |
Liam |
| Before |
5 u |
2 u |
| Change |
- 12 |
|
| After |
1x1 =
1 u |
2x1 =
2 u |
The number of marbles that Liam had remains the same. Make the number of marbles that Liam had the same. LCM of 2 and 2 is 2.
Number of marbles that Tim lost
= 5 u - 1 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of marbles that Liam had in the end
= 2 u
= 2 x 3
= 6
Answer(s): 6
