Eric and Ian shared some buttons. Eric took
37 of the buttons. After Eric lost 16 buttons, Ian had four times as many buttons as Eric. How many buttons did Ian have in the end?
|
Eric |
Ian |
Before |
3 u |
4 u |
Change |
- 16 |
|
After |
1x1 = 1 u |
4x1 = 4 u |
The number of buttons that Ian had remains the same. Make the number of buttons that Ian had the same. LCM of 4 and 4 is 4.
Number of buttons that Eric lost
= 3 u - 1 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of buttons that Ian had in the end
= 4 u
= 4 x 8
= 32
Answer(s): 32