Albert and Sam shared some pens. Albert took
37 of the pens. After Albert lost 16 pens, Sam had four times as many pens as Albert. How many pens did Sam have in the end?
| |
Albert |
Sam |
| Before |
3 u |
4 u |
| Change |
- 16 |
|
| After |
1x1 =
1 u |
4x1 =
4 u |
The number of pens that Sam had remains the same. Make the number of pens that Sam had the same. LCM of 4 and 4 is 4.
Number of pens that Albert lost
= 3 u - 1 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of pens that Sam had in the end
= 4 u
= 4 x 8
= 32
Answer(s): 32
