Cole and Justin shared some buttons. Cole took
57 of the buttons. After Cole lost 12 buttons, Justin had twice as many buttons as Cole. How many buttons did Justin have in the end?
|
Cole |
Justin |
Before |
5 u |
2 u |
Change |
- 12 |
|
After |
1x1 = 1 u |
2x1 = 2 u |
The number of buttons that Justin had remains the same. Make the number of buttons that Justin had the same. LCM of 2 and 2 is 2.
Number of buttons that Cole lost
= 5 u - 1 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of buttons that Justin had in the end
= 2 u
= 2 x 3
= 6
Answer(s): 6