Fabian and Julian shared some pens. Fabian took
57 of the pens. After Fabian lost 12 pens, Julian had twice as many pens as Fabian. How many pens did Julian have in the end?
| |
Fabian |
Julian |
| Before |
5 u |
2 u |
| Change |
- 12 |
|
| After |
1x1 =
1 u |
2x1 =
2 u |
The number of pens that Julian had remains the same. Make the number of pens that Julian had the same. LCM of 2 and 2 is 2.
Number of pens that Fabian lost
= 5 u - 1 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of pens that Julian had in the end
= 2 u
= 2 x 3
= 6
Answer(s): 6
