Asher and Peter shared some stickers. Asher took
57 of the stickers. After Asher lost 20 stickers, Peter had twice as many stickers as Asher. How many stickers did Peter have in the end?
| |
Asher |
Peter |
| Before |
5 u |
2 u |
| Change |
- 20 |
|
| After |
1x1 =
1 u |
2x1 =
2 u |
The number of stickers that Peter had remains the same. Make the number of stickers that Peter had the same. LCM of 2 and 2 is 2.
Number of stickers that Asher lost
= 5 u - 1 u
= 4 u
4 u = 20
1 u = 20 ÷ 4 = 5
Number of stickers that Peter had in the end
= 2 u
= 2 x 5
= 10
Answer(s): 10
