Howard and Justin shared some buttons. Howard took
37 of the buttons. After Howard lost 16 buttons, Justin had four times as many buttons as Howard. How many buttons did Justin have in the end?
|
Howard |
Justin |
Before |
3 u |
4 u |
Change |
- 16 |
|
After |
1x1 = 1 u |
4x1 = 4 u |
The number of buttons that Justin had remains the same. Make the number of buttons that Justin had the same. LCM of 4 and 4 is 4.
Number of buttons that Howard lost
= 3 u - 1 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of buttons that Justin had in the end
= 4 u
= 4 x 8
= 32
Answer(s): 32