Riordan and Caden shared some pens. Riordan took
511 of the pens. After Riordan lost 14 pens, Caden had twice as many pens as Riordan. How many pens did Caden have in the end?
|
Riordan |
Caden |
Before |
5 u |
6 u |
Change |
- 14 |
|
After |
1x3 = 3 u |
2x3 = 6 u |
The number of pens that Caden had remains the same. Make the number of pens that Caden had the same. LCM of 6 and 2 is 6.
Number of pens that Riordan lost
= 5 u - 3 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Number of pens that Caden had in the end
= 6 u
= 6 x 7
= 42
Answer(s): 42